[QE-users] error in scf calculation using wyckoff positions

Paolo Giannozzi paolo.giannozzi at uniud.it
Thu Jun 20 10:40:18 CEST 2024


You have three types of atoms so no more than three values of 
"starting_magnetization"

Paolo

On 19/06/2024 06:59, Pooja Vyas wrote:
> 	
> Non si ricevono spesso messaggi di posta elettronica da 
> poojavyas at mkbhavuni.edu.in. Informazioni sul perché è importante 
> <https://aka.ms/LearnAboutSenderIdentification>
> 	
> 
> 
> I tried to compute energy of antiferromagnetic (AFM) V3Al using the 
> below script:
> 
> 
> &CONTROL
>    calculation = 'scf'
>    prefix = 'v3al'
>    outdir = './'
>    pseudo_dir = './'
>    tprnfor = .true.
>    tstress = .true.
>    etot_conv_thr =   4.0000000000d-05
>    forc_conv_thr =   1.0000000000d-04
>    verbosity = 'high'
> /
> 
> &SYSTEM
>    ibrav = 0
> ! celldm(1) = 11.512210722
> ! space_group = 225
>    nat = 16
>    ntyp = 3
>    ecutwfc = 60
>    ecutrho = 400
>    occupations = 'smearing'
>    smearing = 'cold'
>    degauss = 0.005
>    nspin = 2
>    starting_magnetization(1)=1
>    starting_magnetization(2)=-1
>    starting_magnetization(3)=1
>    starting_magnetization(4)=-1
>    starting_magnetization(5)=1
>    starting_magnetization(6)=-1
>    starting_magnetization(7)=1
>    starting_magnetization(8)=-1
> /
> 
> &ELECTRONS
>    conv_thr =   8.0000000000d-10
>    mixing_beta =   4.0000000000d-01
> /
> 
> ATOMIC_SPECIES
> Al 26.9815 Al.pbe-nl-rrkjus_psl.1.0.0.UPF
> V1 50.9415 V.pbe-spnl-rrkjus_psl.1.0.0.UPF
> V2 50.9415 V.pbe-spnl-rrkjus_psl.1.0.0.UPF
> 
> ATOMIC_POSITIONS {crystal}
> V2            0.2500000000       0.2500000000       0.7500000000
> V2            0.2500000000       0.2500000000       0.2500000000
> V2            0.7500000000       0.7500000000       0.7500000000
> V2            0.7500000000       0.7500000000       0.2500000000
> V2            0.7500000000       0.2500000000       0.7500000000
> V2            0.2500000000       0.7500000000       0.2500000000
> V2            0.2500000000       0.7500000000       0.7500000000
> V2            0.7500000000       0.2500000000       0.2500000000
> Al            0.0000000000       0.0000000000       0.0000000000
> Al            0.0000000000       0.5000000000       0.5000000000
> Al            0.5000000000       0.0000000000       0.5000000000
> Al            0.5000000000       0.5000000000       0.0000000000
> V1            0.5000000000       0.5000000000       0.5000000000
> V1            0.5000000000       0.0000000000       0.0000000000
> V1            0.0000000000       0.5000000000       0.0000000000
> V1            0.0000000000       0.0000000000       0.5000000000
> 
> K_POINTS automatic
>    10 10 10 0 0 0
> 
> CELL_PARAMETERS angstrom
> 6.092 0.000 0.000
> 0.000 6.092 0.000
> 0.000 0.000 6.092
> 
> -------------------------------------------------------------------------
> 
> But as the iterations proceed, I see that the values of total and 
> absolute magnetisation both approaches zero value.
>       total magnetization       =     0.03 Bohr mag/cell
>       absolute magnetization    =     0.14 Bohr mag/cell (This is at 
> 27th iteration and calculation is still going as energy is not yet 
> converged. So, at final iteration, probably both will become zero)
> 
> Shouldn't atleast the absolute magnetisation be nonzero value? I guess 
> for AFM, only total magnetisation at the end should be zero.
> I'm saying this because when I had performed AFM calculation for 
> chromium, total magnetisation was 0.0 but absolute was 2.28 bohr mag/cell.
> are things going correct? Attached below is the cif file.
> 
> 
> 
> On Tue, Jun 18, 2024 at 4:14 PM Paolo Giannozzi 
> <paolo.giannozzi at uniud.it <mailto:paolo.giannozzi at uniud.it>> wrote:
> 
>     On 6/18/24 08:59, Pooja Vyas wrote:
> 
>      >    space_group = 225
> 
>      > ATOMIC_POSITIONS {crystal_sg}
>      > Al 4a
>      > V1 4b
>      > V2 8c
>      > V3 0.25 0.25 0.75
> 
>      >       Error in routine check_atoms (1):
>      >       atoms #   3 and #   6 overlap!
> 
>     they do: atom V3 overlaps with one of the two positions for atoms V2.
>     See https://www.cryst.ehu.es/cgi-bin/cryst/programs/nph-wp-list
>     <https://www.cryst.ehu.es/cgi-bin/cryst/programs/nph-wp-list> for
>     group 225.
> 
>     4a = 4 atoms in the conventional cell (cubic), 1 atom in the primitive
>     cell (fcc). Same for 4b and 8c. So you have nat=3 (number of Wyckoff
>     positions, not of atoms) and 4 atoms, 1 Al and 3 V, if you set
>     ATOMIC_POSITIONS {crystal_sg}
>     Al 4a
>     V1 4b
>     V2 8c
>     Note that ntyp=3: there are two different types of V atoms, not three.
>     Disclaimer: just guessing
> 
>     Paolo
> 
>      >       stopping ...
>      >
>      >
>      >
>      >
>     ----------------------------------------------------------------------------
>      >
>      > What is causing the issue and what should be changed in the input
>     file?
>      > Any kind of help is appreciated.
>      >
>      >
>      > *Pooja,
>      > *
>      > *Research Scholar,*
>      > *Department of Physics,*
>      > *MKBU,*
>      > *Bhavnagar,*
>      > *Gujarat.*
>      > *
>      > *
>      >
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>     -- 
>     Paolo Giannozzi, Dip. Scienze Matematiche Informatiche e Fisiche,
>     Univ. Udine, via delle Scienze 206, 33100 Udine Italy, +39-0432-558216
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> 

-- 
Paolo Giannozzi, Dip. Scienze Matematiche Informatiche e Fisiche,
Univ. Udine, via delle Scienze 206, 33100 Udine Italy, +39-0432-558216
X SCUOLA ENERGIE RINNOVABILI 16-21/9/2024 - PRE-ISCRIZIONE 
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