[QE-users] Problems with symmetry and accuracy thermo_pw calculation
aleksandr.doma at yahoo.com
aleksandr.doma at yahoo.com
Mon Aug 19 12:35:49 CEST 2024
Hello!
Please help with the following. I got the result of calculating the elastic constants of LKBO (orthorhombic, P212121, Space group 19) using thermo_pw (what='scf_elastic_constants', 'elastic algorithm = 'advanced'). The calculation was done, but I found 2 problems:
1) the resulting matrix is asymmetric: 0.1310416661E+04 0.5760227795E+03 0.3377111274E+03 0 0 0 0.5721874370E+03 0.7221687324E+03 0.3757178266E+03 0 0 0 0.3222687958E+03 0.3774439747E+03 0.1122193660E+04 0 0 0 0 0 0 0.2688418051E+03 0 0 0 0 0 0 0.2782351915E+03 0 0 0 0 0 0 0.2810735472E+03
2) the data do not correspond to experimental results.
Some explanations:I noticed that in half SCF calculations, QE identified the symmetry of the crystal as monoclinic (bravais-lattice index = 12 or -12), and in the others - bravais-lattice index = 8 (orthorhombic). At the start, we received the following symmetry information:
Bravais lattice 8 simple orthorhombic Point group number 8 / 38 D_2 (222)
The coset representatives of the space group with the standard order of operations are:
Fractional translations in crystal coordinates
PGS Fract. transl. (all) Fract. transl. (no shift) SGS
E 1 -0.0000 -0.0000 -0.0000 0.0000 0.0000 0.0000 E 1 2z 2 -0.5000 -0.0000 0.5000 0.0000 0.0000 0.5000 2z1 65 2x 4 0.5000 -0.5000 -0.0000 0.5000 0.0000 0.0000 2x1 67 2y 3 -0.0000 0.5000 -0.5000 0.0000 0.5000 0.0000 2y1 66
PGS = Point group symmetry, SGS = space group symmetry (no shift) means the part of the fractional translation that cannot be removed by an origin shift
Fractional translation shift and origin shift in crystal coordinates
PGS FT shift &Origin shift SGS
E 1 -0.0000 -0.0000 -0.0000 0.0000 0.0000 0.0000 E 1 2z 2 -0.5000 0.0000 0.0000 -0.2500 0.0000 0.0000 2z1 65 2x 4 0.0000 -0.5000 0.0000 0.0000 -0.2500 0.0000 2x1 67 2y 3 0.0000 0.0000 -0.5000 0.0000 0.0000 -0.2500 2y1 66
The origin shift gives the point of application of the symmetry Subtract this vector from all atomic coordinates to have this symmetry centered at the origin
Space group number 19
Space group P2_12_12_1 (group number 19).
The Laue class is D_2h (mmm)
In this class the elastic tensor is
( c11 c12 c13 . . . ) ( c12 c22 c23 . . . ) ( c13 c23 c33 . . . ) ( . . . c44 . . ) ( . . . . c55 . ) ( . . . . . c66 )
It requires all six strains. for a total of 24 scf calculations
In the input file, atomic coordinates were used, the relaxation of which was carried out without considering symmetry (ibrav=0). JTH-LDA data sets were used (ecutwfc = 81 Ry, occupations = 'tetrahedra_opt', conv_thr = 1.D-8).
I would be grateful for any ideas to improve the calculation results.
Thanks,Oleksandr
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.quantum-espresso.org/pipermail/users/attachments/20240819/0384bef4/attachment.html>
More information about the users
mailing list