[Pw_forum] transition state using NEB
Giuseppe Mattioli
giuseppe.mattioli at ism.cnr.it
Mon Feb 2 10:38:13 CET 2015
Dear Ravi
You are using a *very* small cell. Try to calculate the H concentration. It will probably be a huge, unphysical value. Moreover, the localized H
(probably a covalent hydride H- in a metal) is strongly interacting with its periodically replicated images, which are at a very short distance.
Try to use a larger supercell and see how much the results change.
HTH
Giuseppe
On Friday, January 30, 2015 05:13:18 PM Ravi Kiran wrote:
> Hi,
>
> I am using neb to calculate activation energy of hydrogen in unit cell of
> nickel. I have placed hydrogen in octahedral position and I am moving it to
> another octahedral position as shown below. My question is whether neb can
> calculates transition state which is tetrahedral site?. I have used a
> path_thr of 0.01eV with 7 images. I have calculated the activation energy
> which I am getting is 1.05 eV as shown in output, whereas the experiments
> indicate 0.42.
>
> *input *
>
> FIRST_IMAGE
> ATOMIC_POSITIONS crystal
> Ni 0 0 0
> Ni 0 0.5 0.5
> Ni 0.5 0 0.5
> Ni 0.5 0.5 0
> H 0.5 0.5 0.5
> LAST_IMAGE
> ATOMIC_POSITIONS crystal
> Ni 0 0 0
> Ni 0 0.5 0.5
> Ni 0.5 0 0.5
> Ni 0.5 0.5 0
> H 0.0 0.5 0.0
> END_POSITIONS
> *output*
> ------------------------------ iteration 56 ------------------------------
>
> tcpu = 6675.4 self-consistency for image 1
> tcpu = 6683.4 self-consistency for image 2
> tcpu = 6764.1 self-consistency for image 3
> tcpu = 6846.9 self-consistency for image 4
> tcpu = 6948.8 self-consistency for image 5
> tcpu = 7031.7 self-consistency for image 6
> tcpu = 7113.1 self-consistency for image 7
>
> activation energy (->) = 1.024248 eV
> activation energy (<-) = 1.024248 eV
>
> image energy (eV) error (eV/A) frozen
>
> 1 -4690.3920838 0.000000 F
> 2 -4690.3237895 0.006072 F
> 3 -4689.7348781 0.005158 F
> 4 -4689.3678358 0.006904 F
> 5 -4689.7349752 0.004005 F
> 6 -4690.3237535 0.006484 F
> 7 -4690.3920838 0.000000 F
>
> path length = 5.711 bohr
> inter-image distance = 0.952 bohr
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