[Pw_forum] What happens at REALLY large ectuwfc?
Brad Malone
brad.malone at gmail.com
Mon Jan 25 23:09:15 CET 2010
>start with 'random' or 'atomic+random' initial wavefunctions
>(startingwfc='...'). I didn't find anything wrong with very
>high cutoffs. Occasionally you can end up in the wrong ground
>state, though, especially in highly symmetric cases like the
>Si example you sent.
Hi Paolo. I tried startingwfc='random' and the eigenvalues are now
essentially the same as the 200 Ry calculation.
------------------------------------------------
k = 0.0000 0.0000 0.0000 (****** PWs) bands (ev):
-5.1746 7.0369 7.0369 7.0369
! total energy = -14.59208472 Ry
Harris-Foulkes estimate = -14.59208472 Ry
estimated scf accuracy < 3.8E-11 Ry
The total energy is the sum of the following terms:
one-electron contribution = 5.58227211 Ry
hartree contribution = 1.67255887 Ry
xc contribution = -5.04795092 Ry
ewald contribution = -16.79896478 Ry
Fock energy 1 = 0.00000000 Ry
Fock energy 2 = 0.00000000 Ry
Half Fock energy 2 = 0.00000000 Ry
----------------------------------------------------------------
Thanks,
Brad
On Sun, Jan 24, 2010 at 2:38 PM, Brad Malone <brad.malone at gmail.com> wrote:
> >are you using the latest cvs version? apparently there is a problem
> >with the new symmetrization algorithm that will be fixed ASAP.
>
> The results I posted are from espresso-4.0.5, although I originally saw
> this problem with espresso-4.1.1 in a different system (AlAs on a 2x2x2
> shifted grid).
>
> As for what Lorenzo said, it makes sense with what I'm seeing. The energy
> breakdowns for the 200 Ry and the 2000 Ry cases are shown below:
>
> For 200 Ry:
> --------------------------------
> ! total energy = -14.59208467 Ry
> Harris-Foulkes estimate = -14.59208467 Ry
> estimated scf accuracy < 3.9E-11 Ry
>
> The total energy is the sum of the following terms:
>
> one-electron contribution = 5.58227319 Ry
> hartree contribution = 1.67255719 Ry
> xc contribution = -5.04795028 Ry
> ewald contribution = -16.79896478 Ry
> Fock energy 1 = 0.00000000 Ry
> Fock energy 2 = 0.00000000 Ry
> Half Fock energy 2 = 0.00000000 Ry
> -------------------------
> For 2000 Ry:
> -------------------------
> ! total energy = -14.11008918 Ry
> Harris-Foulkes estimate = -14.11008918 Ry
> estimated scf accuracy < 1.0E-11 Ry
>
> The total energy is the sum of the following terms:
>
> one-electron contribution = 6.07256114 Ry
> hartree contribution = 1.58024935 Ry
> xc contribution = -4.96393489 Ry
> ewald contribution = -16.79896478 Ry
> Fock energy 1 = 0.00000000 Ry
> Fock energy 2 = 0.00000000 Ry
> Half Fock energy 2 = 0.00000000 Ry
> -------------------
>
> So you can see the one-electron contribution going up and the hartree
> contribution going down as Lorenzo as argued.
>
> Brad
>
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