[QE-users] Acoustic Sum Rule Frequency Question

Tang, Weilun [M S E] weilunt at iastate.edu
Sat Nov 1 00:55:28 CET 2025


Dear Quantum Espresso users,

I made a phonon calculation for an isolated molecule using acoustic sum rule asr='zero-dim'. Then, I compared the phonon modes before and after applying the acoustic sum rule. I noticed that there is a mode that has a huge change in frequency, as shown below. More specifically, the 441.1 cm-1 mode seems to be shifted to 115.30 cm-1 after applying the acoustic sum rule. Is this normal?

For this calculation, I used lower threshold: forc_conv_thr = 1.0D-6, etot_conv_thr = 1.0D-6, conv_thr = 1.D-14 for pw.x. And for phx, I use tr2_ph=1.0d-18.
-------------------------------------------------------------
Below is phonon modes from ph.x:

      Mode symmetry, D_3h (-62m) point group:

        freq (   1-   1) =        -27.8  [cm-1]   --> A'_2
        freq (   2-   3) =         65.6  [cm-1]   --> E''             R
        freq (   4-   4) =        103.9  [cm-1]   --> A''2            I
        freq (   5-   6) =        120.4  [cm-1]   --> E''             R
        freq (   7-   8) =        146.2  [cm-1]   --> E'              I+R
        freq (   9-  10) =        188.8  [cm-1]   --> E'              I+R
        freq (  11-  11) =        367.1  [cm-1]   --> A'_1            R
        freq (  12-  13) =        430.7  [cm-1]   --> E'              I+R
        freq (  14-  14) =        441.1  [cm-1]   --> A''2            I
        freq (  15-  15) =        461.4  [cm-1]   --> A'_2
        freq (  16-  17) =        631.9  [cm-1]   --> E''             R
        freq (  18-  18) =        776.4  [cm-1]   --> A''2            I
        freq (  19-  20) =        801.0  [cm-1]   --> E'              I+R
        freq (  21-  21) =        907.1  [cm-1]   --> A'_1            R
        freq (  22-  22) =       1101.1  [cm-1]   --> A'_2
        freq (  23-  24) =       1150.0  [cm-1]   --> E'              I+R
        freq (  25-  25) =       1189.0  [cm-1]   --> A'_1            R
        freq (  26-  27) =       1337.2  [cm-1]   --> E'              I+R
----------------------------------------------------------------
Below is output from dynmat.x

     Reading Dynamical Matrix from file dmat.ttc
     ...Force constants read
     ...epsilon and Z* read
     ...Raman cross sections read
     Acoustic Sum Rule: || Z*(ASR) - Z*(orig)|| =    1.029894E+00
     Acoustic Sum Rule: ||dyn(ASR) - dyn(orig)||=    2.701556E-01
     A direction for q was not specified:TO-LO splitting will be absent

     Polarizability (A^3 units)
     multiply by 0.759092 for Clausius-Mossotti correction
       262.517180   -0.000000   -0.000000
        -0.000000  262.517180   -0.000000
         0.000000    0.000000   57.305445

     IR activities are in (D/A)^2/amu units
     Raman activities are in A^4/amu units
     multiply Raman by 0.576221 for Clausius-Mossotti correction

# mode   [cm-1]    [THz]      IR          Raman   depol.fact
    1     -0.00   -0.0000    0.0000        16.3234    0.7500
    2     -0.00   -0.0000    0.0000      3355.0146    0.7500
    3     -0.00   -0.0000    0.0000      1478.4689    0.7500
    4      0.00    0.0000    0.0000       285.5435    0.7500
    5      0.00    0.0000    0.0000       873.4000    0.7500
    6      0.00    0.0000    0.0000      1623.8289    0.7500
    7     73.38    2.1998    0.0000       696.8190    0.7500
    8     73.38    2.1998    0.0000       696.8152    0.7500
    9    115.30    3.4567    0.2787         0.0000    0.7500
   10    177.24    5.3134    1.7092     44473.2909    0.7500
   11    177.24    5.3134    1.7092     44473.2914    0.7500
   12    367.09   11.0050    0.0000  11288132.4685    0.1106
   13    436.75   13.0934    0.2992      3721.4221    0.7500
   14    436.75   13.0934    0.2992      3721.4231    0.7500
   15    462.38   13.8617    0.0000         0.0004    0.7500
   16    631.59   18.9347    0.0000     13677.2759    0.7500
   17    631.59   18.9347    0.0000     13677.2842    0.7500
   18    778.46   23.3377    0.0792         0.0000    0.7500
   19    802.57   24.0605   12.9665   1800840.5786    0.7500
   20    802.57   24.0605   12.9665   1800840.5109    0.7500
   21    907.11   27.1945    0.0000   8355726.6168    0.1191
   22   1101.10   33.0101    0.0000         0.0000    0.7500
   23   1150.13   34.4801   26.2055  16251271.1703    0.7500
   24   1150.13   34.4801   26.2055  16251270.4526    0.7500
   25   1189.02   35.6458    0.0000     16979.5440    0.2674
   26   1337.59   40.1000   27.2231  16068754.7864    0.7500
   27   1337.59   40.1000   27.2231  16068754.1344    0.7500

--------------------------------------------------------------------------------------------------------
Below is my input file for pw.x

&CONTROL
  calculation  = "scf",
  prefix       = "ttc",
  pseudo_dir   = "/home/weilunt/pseudopotential/norm_conserving/pz",
  outdir       = "./tmp",
  forc_conv_thr = 1.0D-6,
  etot_conv_thr = 1.0D-6,

/
&SYSTEM
  assume_isolated = 'martyna-tuckerman',
  ibrav     = 4,
  A = 17.2,
  C = 10,
  nat       = 9,
  ntyp      = 3,
  ecutwfc   = 80.D0, !better 120
  tot_charge = -3,
  occupations = 'fixed',
/
&ELECTRONS
  conv_thr    = 1.D-14,
  mixing_beta = 0.7,
  electron_maxstep = 200,
/
&IONS
/
ATOMIC_SPECIES
  S 32.070  S.pz-hgh.UPF
  N 14.007  N.pz-hgh.UPF
  C 12.010  C.pz-hgh.UPF
ATOMIC_POSITIONS (angstrom)
S                0.0000000000       -3.0749791762       -0.0000000000
S               -2.6627598154        1.5374395881       -0.0000000000
S                2.6627598154        1.5374395881        0.0000000000
N                1.1913527585       -0.6879250817       -0.0000000000
N               -1.1913527585       -0.6879250817        0.0000000000
N                0.0000000000        1.3757501635        0.0000000000
C                0.0000000000       -1.3240902237       -0.0000000000
C               -1.1466139383        0.6620951119        0.0000000000
C                1.1466139383        0.6620951119        0.0000000000
K_POINTS (automatic)
1 1 1 0 0 0
-----------------------------------------------------------------------------------------

Thank you for your time and your help in advance,

Weilun Tang


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