[QE-users] normalization of wfcs (wfck2r)
Davide Ceresoli
davide.ceresoli at cnr.it
Thu Aug 26 14:00:44 CEST 2021
Dear Chris,
you don't need the volume, just to divide by (n1*n2*n3).
Best,
D.
On 8/26/21 6:24 AM, Christoph Wolf wrote:
> Dear all,
>
> I am converting a wave-function from k to R space using wfck2r.x. There is only
> 1 k-point (particle in a box of 15*15*15 Ang) and the wfc looks like:
>
> ==== e( 8) = -4.84501 eV ====
> psi = 0.998*[# 2]
> |psi|^2 = 0.999
>
> state # 2: atom 1 (Fe ), wfc 2 (l=0 m= 1)
>
> So this is a "pure s state"; i converte the wfc into real space by using:
>
> first_k = 1,
> last_k = 1,
> first_band = 8
> last_band = 8
>
> and I get an ".oct" (plain text) file containing on a grid of 144 x 144 x144:
>
> (*-0.885667802907E+01*, 0.607695317678E-16)
> ( *-0.627285985227E+01*, -0.418670474801E-15)
> ( -0.291716024900E+01, -0.436306625693E-15)
> ....
> ..
>
> if I understood the manual correctly the order is such that the real part for
> example:
>
> re[:,:,0]= [ *-8.85667803, * *-6.02698044, * -2.39305522, ..., -12.45808728,
> -11.95557896, -10.79190254]
>
> that is the first 144*144 elements belong to z=0, the next to z=1, z=2, ...z=144.
>
> my volume element would be: (15/0.529)**3/144**3=0.0076 (au^3/grid^3)
>
> if I take the dot product of the complex wfc
> <psi*|psi>*0.076=25733.51243066387+0j, but should this not be the same as
> |psi|^2 = 0.999?
>
> This is probably a very stupid and obvious mistake but I have been looking at
> this for a while now and don't get it...
>
> Best,
> Chris
> --
> Group Leader "Theory of Quantum Systems at Surfaces"
> IBS Center for Quantum Nanoscience
> Seoul, South Korea
--
+--------------------------------------------------------------+
Davide Ceresoli
CNR - Istituto di Scienze e Tecnologie Chimiche (SCITEC)
c/o University of Milan, via Golgi 19, 20133 Milan, Italy
Email: davide.ceresoli at cnr.it
Phone: +39-02-50314276, +39-347-1001570 (mobile)
Skype: dceresoli
Website: http://sites.google.com/site/dceresoli/
+--------------------------------------------------------------+
More information about the users
mailing list