[QE-users] [Pw_forum] How to calculate atomic magnetic moment in the non-collinear spin-orbit calculations

Lorenzo Paulatto paulatz at gmail.com
Fri Dec 11 17:17:05 CET 2020


On 2020-12-11 16:38, Ming Lei wrote:
> Dear Lorenzo and Marcelo,
>
> Thank you for your reply. The Lowdin Charges I post was calculated by 
> setting
>
>  noncolin = .true.
>  lspinorb = .true.
>  angle1(1)=0.0
>  angle2(1)=0.0

Yes, I had not thought about full-relativistic calculations. That said, 
if you do not specify any starting_magnetization, the polarization will 
be zero, I can tell you this without the need to do any projection. On 
the other hand, if you set a starting_magnetization, the pw.x code will 
write-out the polarization itself:


  ==============================================================================
      atom number    5 relative position :    0.0000   0.0000 0.0000
      charge :     5.377640
      magnetization :          0.000000    0.000000   -0.000000
      magnetization/charge:    0.000000    0.000000   -0.000000
      polar coord.: r, theta, phi [deg] :     0.000000  180.000000 
360.000000
  ==============================================================================

I don think projwfc gives you the polarization in output in this case, 
but what's above may be enough for your need.


cheers



>
> This is the case of nspin = 4 (nspin = 4 : spin-polarized calculation, 
> noncollinear (magnetization in generic direction) DO NOT specify nspin 
> <https://www.quantum-espresso.org/Doc/INPUT_PW.html#nspin>in this 
> case; specify noncolin 
> <https://www.quantum-espresso.org/Doc/INPUT_PW.html#noncolin>=.TRUE. 
> instead). When noncolin = .true., the Lowdin charges don't have the 
> information about atom magnetic moment.
>
> I tried nspin = 2 before, and I had spin-up and spin-down Lowdin 
> charges when nspin =2, but this is not a spin-polarized calculation.
>
> So besides projwfc, is there any other way to obtain information about 
> the atomic magnetic moment? For example, in the pp.x, plot_num = 13 is 
> the noncollinear magnetization. But after running pp.x, I don't know 
> how to get the atomic magnetic moment.
>
> Ming Lei
> University of California, Riverside
>
>
> On Fri, Dec 11, 2020 at 3:33 AM Marcelo Albuquerque 
> <marcelofilho at id.uff.br <mailto:marcelofilho at id.uff.br>> wrote:
>
>     Dear Ming,
>
>     I completely agree with Mr. Paullato, but, more precisely, in the
>     case of non-collinear calculations, you have to specify nspin = 4,
>     actually.
>     There are other options you have to deal with in other to perform
>     such a task. Please check the documentation below, as well as the
>     corresponding projwfc.x one:
>
>     https://www.quantum-espresso.org/Doc/INPUT_PW.html#idm368
>
>     HIH.
>
>     Best of luck.
>     /
>     /
>     /
>     /   Marcelo Albuquerque/
>     //
>     /     Ph.D. Candidate/
>     //
>     /   Physics Institute/
>     //
>     /Universidade Federal Fluminense (UFF)/
>     /
>     /     Niterói/RJ - Brazil/
>
>
>     On Fri, Dec 11, 2020 at 8:00 AM Lorenzo Paulatto wrote:
>
>
>         Dear Ming,
>
>         the projwfc will compute spin-up and spin-down Lowdin charges,
>         but only
>         if you did include spin in your pw calculation, by setting
>         nspin=2.
>
>         kind reagrds
>
>
>         On 2020-12-11 06:34, Ming Lei wrote:
>         > Dear Users,
>         >
>         > After running projwfc.x, at the end of the output file, it shows
>         >
>         > Lowdin Charges:
>         >
>         > ? ? ?Atom # ? 1: total charge = ?13.5212, s, p, d, f =
>         2.6218 ?5.9990
>         > ?4.9003
>         > ? ? ?Atom # ? 2: total charge = ?13.5212, s, p, d, f =
>         2.6218 ?5.9990
>         > ?4.9003
>         > ? ? ?Atom # ? 3: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Atom # ? 4: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Atom # ? 5: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Atom # ? 6: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Atom # ? 7: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Atom # ? 8: total charge = ? 7.0913, s, p, d, f =
>         1.9097 ?5.1816
>         > ?0.0000
>         > ? ? ?Spilling Parameter: ? 0.0059
>         >
>         > There is no information about the?magnetic moment of each
>         atom.? So
>         > how to?calculate atomic magnetic moment in the non-collinear
>         > spin-orbit calculations?
>         >
>         > Any suggestion will?be appreciated. Thank you.
>         >
>         > Ming Lei
>         > University of California, Riverside
>         >
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