[QE-users] hai,
Paolo Giannozzi
p.giannozzi at gmail.com
Thu Mar 14 23:10:35 CET 2019
You are thinking to the so-called "conventional" (simple cubic) cell, but
QE uses the "primitive" (smallest) cell
Paolo
On Thu, Mar 14, 2019 at 7:17 PM yasmin kani <yasminkani8 at gmail.com> wrote:
> I can't understand the concept ibrav used in QE. because ibrav=2 defines
> fcc lattice. In fcc there are four atoms per unit cell but we give nat=2.
> why?
> _______________________________________________
> users mailing list
> users at lists.quantum-espresso.org
> https://lists.quantum-espresso.org/mailman/listinfo/users
--
Paolo Giannozzi, Dip. Scienze Matematiche Informatiche e Fisiche,
Univ. Udine, via delle Scienze 208, 33100 Udine, Italy
Phone +39-0432-558216, fax +39-0432-558222
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.quantum-espresso.org/pipermail/users/attachments/20190314/86f484c2/attachment.html>
More information about the users
mailing list