[Pw_forum] Symmetry recognition

Pascal Boulet pascal.boulet at univ-amu.fr
Fri Feb 24 18:07:06 CET 2017


Hello,

Here is a simple example with Al2O3 of the problem I am facing.

The initial 'vc-relax' calculation is performed with the input file (partial informations here):
&SYSTEM
  ibrav          = 5,
  a              = 5.12,
  b              = 5.12,
  c              = 5.12,
  cosac          = 0.56956647,
  space_group    = 167,
  nat            = 2,
  ntyp           = 2,
…
/

ATOMIC_POSITIONS crystal_sg
Al 0.355 0.355 0.355
O  0.553 -0.053 0.25

The output file shows:

     bravais-lattice index     =            5
     lattice parameter (alat)  =       9.6754  a.u.
     unit-cell volume          =     905.7461 (a.u.)^3
     number of atoms/cell      =           10
… 
     celldm(1)=   9.675398  celldm(2)=   1.000000  celldm(3)=   1.000000
     celldm(4)=   0.000000  celldm(5)=   0.000000  celldm(6)=   0.000000

     crystal axes: (cart. coord. in units of alat)
               a(1) = (   0.707107  -0.408248   0.577350 )  
               a(2) = (   0.000000   0.816497   0.577350 )  
               a(3) = (  -0.707107  -0.408248   0.577350 )  
… 
    12 Sym. Ops., with inversion, found ( 6 have fractional translation)
… 
     point group D_3d (-3m)
… 
   Crystallographic axes

     site n.     atom                  positions (cryst. coord.)
         1           Al  tau(   1) = (  0.3550000  0.3550000  0.3550000  )
         2           Al  tau(   2) = (  0.1450000  0.1450000  0.1450000  )
         3           Al  tau(   3) = (  0.6450000  0.6450000  0.6450000  )
         4           Al  tau(   4) = (  0.8550000  0.8550000  0.8550000  )
         5           O   tau(   5) = (  0.2500000  0.5530000  0.9470000  )
         6           O   tau(   6) = (  0.5530000  0.9470000  0.2500000  )
         7           O   tau(   7) = (  0.9470000  0.2500000  0.5530000  )
         8           O   tau(   8) = (  0.7500000  0.4470000  0.0530000  )
         9           O   tau(   9) = (  0.4470000  0.0530000  0.7500000  )
        10           O   tau(  10) = (  0.0530000  0.7500000  0.4470000  )

     number of k points=    60

I make the calculation intentionally fail to restart it. In the restart input file I change  restart_mode  = ‘from_scratch’, by   restart_mode  = ‘restart’.
I also have to add startingpot  = ‘atomic’, and startingwfc  = 'atomic+random’ … the wfc files are not present for some reasons… I have to find why is this.

The new output file shows:

     Atomic positions and unit cell read from directory:
     ./al2o3.save/
… 
     bravais-lattice index     =            5
     lattice parameter (alat)  =       9.6754  a.u.
     unit-cell volume          =     905.7461 (a.u.)^3
     number of atoms/cell      =           10
… 
     celldm(1)=   9.675398  celldm(2)=   1.000000  celldm(3)=   1.000000
     celldm(4)=   0.000000  celldm(5)=   0.000000  celldm(6)=   0.000000

     crystal axes: (cart. coord. in units of alat)
               a(1) = (   0.707107  -0.408248   0.577350 )  
               a(2) = (   0.000000   0.816497   0.577350 )  
               a(3) = (  -0.707107  -0.408248   0.577350 )  
… 
     3 Sym. Ops. (no inversion) found
… 
     point group C_3 (3)
… 
   Crystallographic axes

     site n.     atom                  positions (cryst. coord.)
         1           Al  tau(   1) = (  0.3798376  0.3798376  0.3798376  )
         2           Al  tau(   2) = (  0.1201624  0.1201624  0.1201624  )
         3           Al  tau(   3) = (  0.7202472  0.7202472  0.7202472  )
         4           Al  tau(   4) = (  1.0218300  1.0218300  1.0218300  )
         5           O   tau(   5) = (  0.4065635  0.6450760  0.9807839  )
         6           O   tau(   6) = (  0.6450760  0.9807839  0.4065635  )
         7           O   tau(   7) = (  0.9807839  0.4065635  0.6450760  )
         8           O   tau(   8) = (  0.7548213  0.5163088  0.1806009  )
         9           O   tau(   9) = (  0.5163088  0.1806009  0.7548213  )
        10           O   tau(  10) = (  0.1806009  0.7548213  0.5163088  )

     number of k points=    88



Is it numerical or am I doing something wrong?

I join a tarball file with all the data if useful.

Thank you for your help,
Pascal


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Le 23 févr. 2017 à 21:45, Paolo Giannozzi <p.giannozzi at gmail.com> a écrit :

> Of course there is a reason, but not necessarily a good one. If you
> are "restarting from an incomplete calculation", I guess that the code
> overwrites the input coordinates with the current ones. The symmetry
> should be the same, but sometimes numerical noise breaks the symmetry.
> It is impossible to say more without an example.
> 
> Paolo
> 
> On Thu, Feb 23, 2017 at 8:56 AM, Pascal Boulet
> <pascal.boulet at univ-amu.fr> wrote:
>> Dear all,
>> 
>> I am running a structural optimization with QE 6.0. The structure is
>> orthorhombic, ibrav=8, with 8 symmetry elements. The first run did not
>> converge so I have to restart it. But as I restart it, the number of
>> symmetry is now 4, there is a descent of symmetry. I shall say that I use
>> the space_group option with COORDINATES crystal_sg. But the problem remains
>> if I put all the coordinates (unsurprisingly).
>> 
>> Is there a reason for this, and can I avoid this?
>> 
>> Thank you
>> Best regards
>> Pascal
>> 
>> -
>> Pascal Boulet - MCF HDR, Resp. L2 MPCI - DEPARTEMENT CHIMIE
>> Aix-Marseille Université - ST JEROME - Avenue Escadrille Normandie Niemen -
>> 13013 Marseille
>> Tél: +33(0)4 13 55 18 10 - Fax : +33(0)4 13 55 18 50
>> Site : http://madirel.univ-amu.fr/pages_web_BOULET_PASCAL/annuaire - Email :
>> pascal.boulet at univ-amu.fr
>> 
>> 
>> 
>> 
>> 
>> _______________________________________________
>> Pw_forum mailing list
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> 
> 
> 
> -- 
> Paolo Giannozzi, Dip. Scienze Matematiche Informatiche e Fisiche,
> Univ. Udine, via delle Scienze 208, 33100 Udine, Italy
> Phone +39-0432-558216, fax +39-0432-558222
> 
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