[Pw_forum] pdos

[ashkan shekaari]

Dear experts,

in quantum mechanics, the quantum number *m* is between *-l *and* l *:
-l<=m<=l

and so m=-1, 0, +1 for l=1. but in the output of a pdos calculation, values
of m

are seen as follows:

     state #   9: atom   1 (Mo ), wfc  5 (l=2 m= 1)
     state #  10: atom   1 (Mo ), wfc  5 (l=2 m= 2)
     state #  11: atom   1 (Mo ), wfc  5 (l=2 m= 3)
     state #  12: atom   1 (Mo ), wfc  5 (l=2 m= 4)
     state #  13: atom   1 (Mo ), wfc  5 (l=2 m= 5)

Is, for example,  (l=2 , m= 1) equivalent to m=-2 or

     (l=2 m= 1)------>  m=-2
     (l=2 m= 2)------>  m=-1
      (l=2 m= 3)------>  m=0
      (l=2 m= 4)------>  m=1
      (l=2 m= 5)------>  m=2

?

*--*
*All the best,*
*Ashkan Shekaari*
*Plasma Physics Research Center, Science and Research Branch, *
*I A U, 14778-93855 Tehran, Iran.*

On Sun, May 8, 2016 at 12:06 AM, ashkan shekaari <shekaari at gmail.com> wrote:

> Dear experts,
>
> in quantum mechanics, the quantum number *m* is between *-l *and* l *:
> -l<=m<=l
>
> and so m=-1, 0, +1. but in the output of a pdos calculation, values of m
>
> are seen as follows:
>
>      state #   9: atom   1 (Mo ), wfc  5 (l=2 m= 1)
>      state #  10: atom   1 (Mo ), wfc  5 (l=2 m= 2)
>      state #  11: atom   1 (Mo ), wfc  5 (l=2 m= 3)
>      state #  12: atom   1 (Mo ), wfc  5 (l=2 m= 4)
>      state #  13: atom   1 (Mo ), wfc  5 (l=2 m= 5)
>
> Is, for example,  (l=2 , m= 1) equivalent to m=-2 or
>
>      (l=2 m= 1)------>  m=-2
>      (l=2 m= 2)------>  m=-1
>       (l=2 m= 3)------>  m=0
>       (l=2 m= 4)------>  m=1
>       (l=2 m= 5)------>  m=2
>
> ?
>
> *--*
> *All the best,*
> *Ashkan Shekaari*
> *Plasma Physics Research Center, Science and Research Branch, *
> *I A U, 14778-93855 Tehran, Iran.*
>
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