[Pw_forum] A question on atomic magnetic moments
Srijan Kumar Saha
srijan.india at gmail.com
Mon Feb 14 12:15:45 CET 2011
Dear QE users,
QE is able to find the correct symmetry for the input file, added at the
end of this email.
Here is the proof:
48 Sym.Ops. (with inversion).
However, during vc-relax it breaks the symmetry.
Proof goes here:
0.000000000 0.000000000 0.000000000
0.250189867 0.250189867 0.250189867
0.000000000 0.250189689 0.250189689
0.250189689 0.000000000 0.250189689
0.250189689 0.250189689 0.000000000
0.500379494 0.000000000 0.000000000
0.750569121 0.250189867 0.250189867
0.500379494 0.250189728 0.250189728
0.750569299 0.000000000 0.250189689
0.750569299 0.250189689 0.000000000
0.000000000 0.500379494 0.000000000
0.250189867 0.750569121 0.250189867
0.000000000 0.750569299 0.250189689
0.250189728 0.500379494 0.250189728
0.250189689 0.750569299 0.000000000
0.500379494 0.500379494 0.000000000
0.750569121 0.750569121 0.250189867
0.500379494 0.750569260 0.250189728
0.750569260 0.500379494 0.250189728
0.750569299 0.750569299 0.000000000
0.000000000 0.000000000 0.500379494
0.250189867 0.250189867 0.750569121
0.000000000 0.250189689 0.750569299
0.250189689 0.000000000 0.750569299
0.250189728 0.250189728 0.500379494
0.500379494 0.000000000 0.500379494
0.750569121 0.250189867 0.750569121
0.500379494 0.250189728 0.750569260
0.750569299 0.000000000 0.750569299
0.750569260 0.250189728 0.500379494
0.000000000 0.500379494 0.500379494
0.250189867 0.750569121 0.750569121
0.000000000 0.750569299 0.750569299
0.250189728 0.500379494 0.750569260
0.250189728 0.750569260 0.500379494
0.500379494 0.500379494 0.500379494
0.750569121 0.750569121 0.750569121
0.500379494 0.750569260 0.750569260
0.750569260 0.500379494 0.750569260
0.750569260 0.750569260 0.500379494
Is this possible to keep symmetry of the initial system conserved during
vc-relax with BFGS ?
Input file:
&control
calculation='vc-relax'
restart_mode='from_scratch',
prefix='pbmno',
tstress = .true.
tprnfor = .true.
wf_collect=.true.
verbosity='high'
etot_conv_thr=1.0D-5,
forc_conv_thr=1.0D-4,
/
&system
ibrav = 1,
nat = 40,
ntyp=3,
celldm(1)=20.70
nosym=.FALSE.
ecutwfc = 30.0,
ecutrho = 240.0,
occupations='smearing',
smearing='fd',
degauss=0.005d0,
nspin=2
starting_magnetization(2)=1.0,
/
&electrons
diagonalization = 'david'
conv_thr = 1.0d-9
mixing_beta = 0.7
/
&ions
/
&cell
/
ATOMIC_SPECIES
Pb 1.0 Pb.UPF
Mn 1.0 Mn.UPF
O 1.0 O.UPF
ATOMIC_POSITIONS (alat)
Pb 0.00 0.00 0.00
Mn 0.25 0.25 0.25
O 0.00 0.25 0.25
O 0.25 0.00 0.25
O 0.25 0.25 0.00
Pb 0.50 0.00 0.00
Mn 0.75 0.25 0.25
O 0.50 0.25 0.25
O 0.75 0.00 0.25
O 0.75 0.25 0.00
Pb 0.00 0.50 0.00
Mn 0.25 0.75 0.25
O 0.00 0.75 0.25
O 0.25 0.50 0.25
O 0.25 0.75 0.00
Pb 0.50 0.50 0.00
Mn 0.75 0.75 0.25
O 0.50 0.75 0.25
O 0.75 0.50 0.25
O 0.75 0.75 0.00
Pb 0.00 0.00 0.50
Mn 0.25 0.25 0.75
O 0.00 0.25 0.75
O 0.25 0.00 0.75
O 0.25 0.25 0.50
Pb 0.50 0.00 0.50
Mn 0.75 0.25 0.75
O 0.50 0.25 0.75
O 0.75 0.00 0.75
O 0.75 0.25 0.50
Pb 0.00 0.50 0.50
Mn 0.25 0.75 0.75
O 0.00 0.75 0.75
O 0.25 0.50 0.75
O 0.25 0.75 0.50
Pb 0.50 0.50 0.50
Mn 0.75 0.75 0.75
O 0.50 0.75 0.75
O 0.75 0.50 0.75
O 0.75 0.75 0.50
K_POINTS {automatic}
2 2 2 0 0 0
Thanking you and with my best regards,
Srijan K
CCMT
Indian Institute of Science
India 560012
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