[Pw_forum] How to set nbnd value for berry phase calculations?
Lim Chiang Huay, Freda
limch at ihpc.a-star.edu.sg
Wed Jun 30 09:43:52 CEST 2010
Hi all,
I'm doing Berry Phase calculations for the first time for BiFeO3. I met with some problems in setting nbnd values for the scf and nscf calculations. And I can't find an answer in previous forum post.
I used the pseudopotentials available in the website http://www.pwscf.org/pseudo.php
They are:
Bi.pbe-d-mt.UPF
Fe.pbe-nd-rrkjus.UPF
O.pbe-mt.UPF
and from the pseudopotentials, there should be 41 electrons in a cell. From the manual nbnd = nelect/2.
I've tried different combinations of nbnd values for scf and nscf jobs and non was able to give me the polarization value.
The following are the some selected cases and their error msg:
Case(1)
*.scf, nbnd=21; *.nscf, nbnd=21
Both jobs crash
Error for scf: too few bands
Error for nscf: starting and expected charges differ
Case(2)
*.scf, nbnd=43; *.nscf, nbnd=42
Scf converged. Nscf crashed.
Error for nscf: Polarization only for insulators and no empty bands
Case(3)
*.scf, nbnd=42; *.nscf, nbnd=42
Scf converged. Nscf crashed.
Error for scf: too few spin up bands
Error for nscf: starting and expected charges differ
My input files are as follows:
SCF JOB:
&control
calculation = 'scf',
restart_mode = 'from_scratch'
pseudo_dir = '/Home6/cc/ihpclimc/BP_CAL/PPOT'
outdir = '/Scratch/ihpclimc/BERRY_PHASE_CALCULATIONS/Try_BP/OUTDIR',
/
&system
ibrav=5
celldm(1)=10.6523,
celldm(4)=0.50988,
nat=10
ntyp=3
nbnd=42
ecutwfc=50.0
occupations = 'fixed'
degauss=0.00
nspin=2
multiplicity=5
lda_plus_u=.true.
Hubbard_U(2)=6
/
&electrons
conv_thr = 1e-12,
mixing_beta=0.3,
diagonalization='cg',
/
ATOMIC_SPECIES
Bi 209.0 Bi.pbe-d-mt.UPF
Fe 55.85 Fe.pbe-nd-rrkjus.UPF
O 16.00 O.pbe-mt.UPF
ATOMIC_POSITIONS crystal
Bi 0.000 0.000 0.000 0 0 0
Bi 0.500 0.500 0.500 0 0 0
Fe 0.219 0.219 0.219
Fe 0.719 0.719 0.719
O 0.445 0.032 0.897
O 0.897 0.445 0.032
O 0.032 0.897 0.445
O 1.397 0.532 0.945
O 0.532 0.945 1.397
O 0.945 1.397 0.532
K_POINTS {automatic}
1 1 1 1 1 1
NSCF JOB:
&control
calculation = 'nscf',
pseudo_dir = '/Home6/cc/ihpclimc/BP_CAL/PPOT'
outdir = '/Scratch/ihpclimc/BERRY_PHASE_CALCULATIONS/Try_BP/OUTDIR',
lberry = .true.
gdir = 3
nppstr = 7
/
&system
ibrav=5
celldm(1)=10.6523,
celldm(4)=0.50988,
nat=10
ntyp=3
nbnd=42
ecutwfc=50.0
occupations = 'fixed'
degauss=0.00
nspin=2
multiplicity=5
lda_plus_u=.true.
Hubbard_U(2)=6
/
&electrons
conv_thr = 1e-12,
mixing_beta=0.3,
diagonalization='cg',
/
ATOMIC_SPECIES
Bi 209.0 Bi.pbe-d-mt.UPF
Fe 55.85 Fe.pbe-nd-rrkjus.UPF
O 16.00 O.pbe-mt.UPF
ATOMIC_POSITIONS crystal
Bi 0.000 0.000 0.000 0 0 0
Bi 0.500 0.500 0.500 0 0 0
Fe 0.219 0.219 0.219
Fe 0.719 0.719 0.719
O 0.445 0.032 0.897
O 0.897 0.445 0.032
O 0.032 0.897 0.445
O 1.397 0.532 0.945
O 0.532 0.945 1.397
O 0.945 1.397 0.532
K_POINTS {automatic}
4 4 4 1 1 1
Can anyone help?
Thanks,
Rgds
Freda Lim
Institute of High Performance Computing
1 Fusionopolis Way, #16-16 Connexis
Singapore 138632
Email: limch at ihpc.a-star.edu.sg<mailto:limch at ihpc.a-star.edu.sg>
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