[Pw_forum] how to consider the "dt" flag during vc-relax
Chaohao Hu
chaohao.mse at gmail.com
Tue Oct 23 13:57:23 CEST 2007
Wow, the convergence is good when the "dt" flag is further reduced to 30
considering my special system in which it only contains some light elements.
Thanks Dr. Axel and Cesar again for your suggestion -:)
==========
total stress (Ry/bohr**3) (kbar) P= -
7.01
total stress (Ry/bohr**3) (kbar) P= -
6.21
total stress (Ry/bohr**3) (kbar) P= -
5.28
total stress (Ry/bohr**3) (kbar) P= -
4.38
total stress (Ry/bohr**3) (kbar) P= -
3.39
total stress (Ry/bohr**3) (kbar) P= -
2.40
total stress (Ry/bohr**3) (kbar) P= -
1.49
total stress (Ry/bohr**3) (kbar) P= -
0.61
total stress (Ry/bohr**3) (kbar) P=
0.24
total stress (Ry/bohr**3) (kbar) P=
0.59
total stress (Ry/bohr**3) (kbar) P= -
0.00
total stress (Ry/bohr**3) (kbar) P=
0.14
total stress (Ry/bohr**3) (kbar) P=
0.15
total stress (Ry/bohr**3) (kbar) P=
0.21
total stress (Ry/bohr**3) (kbar) P=
0.24
total stress (Ry/bohr**3) (kbar) P=
0.19
total stress (Ry/bohr**3) (kbar) P=
0.15
total stress (Ry/bohr**3) (kbar) P=
0.13
total stress (Ry/bohr**3) (kbar) P=
0.10
total stress (Ry/bohr**3) (kbar) P=
0.07
total stress (Ry/bohr**3) (kbar) P=
0.07
total stress (Ry/bohr**3) (kbar) P=
0.07
total stress (Ry/bohr**3) (kbar) P=
0.07
total stress (Ry/bohr**3) (kbar) P=
0.03
...
Total force = 0.001176 Total SCF correction = 0.000004
Total force = 0.001374 Total SCF correction = 0.000004
Total force = 0.001858 Total SCF correction = 0.000006
Total force = 0.001973 Total SCF correction = 0.000003
Total force = 0.001762 Total SCF correction = 0.000004
Total force = 0.001475 Total SCF correction = 0.000004
Total force = 0.001355 Total SCF correction = 0.000004
Total force = 0.001877 Total SCF correction = 0.000005
Total force = 0.001823 Total SCF correction = 0.000003
Total force = 0.001150 Total SCF correction = 0.000005
Total force = 0.000929 Total SCF correction = 0.000003
Total force = 0.000917 Total SCF correction = 0.000002
Total force = 0.000931 Total SCF correction = 0.000003
Total force = 0.001003 Total SCF correction = 0.000003
Total force = 0.000736 Total SCF correction = 0.000002
Total force = 0.000728 Total SCF correction = 0.000002
Total force = 0.000749 Total SCF correction = 0.000001
Total force = 0.000747 Total SCF correction = 0.000002
Total force = 0.000692 Total SCF correction = 0.000003
Total force = 0.000751 Total SCF correction = 0.000002
Total force = 0.000872 Total SCF correction = 0.000002
Total force = 0.000671 Total SCF correction = 0.000003
Total force = 0.000723 Total SCF correction = 0.000002
Total force = 0.000715 Total SCF correction = 0.000003
Total force = 0.000620 Total SCF correction = 0.000002
...
Best regards,
C.H.
--
============================
C.H. Hu
Postdoctoral fellow
Chimie et Physico-Chimie appliquees
Institut Francais du Petrole (IFP)
Rueil-Malmaison, France
E_mail: chaohao.mse at gmail.com
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