[Pw_forum] How to calculate the properties of pt Bulk and the pt(111) surface
oulihui666
oulihui666 at 126.com
Fri Oct 19 15:20:24 CEST 2007
Dear pwscf users: Because of the need of research, I tried to calculate the properties of pt Bulk and the pt(111) surface containing 20 pt atoms with pwscf, however,when calculating, error information was found, it displayed:======================================================= "from data_structure: error # 1 too many sticks"======================================================= I am really newbie in this thing, sorry about these naive questions...And this is the input file: Thanks a lot
&CONTROL
calculation = 'scf' ,
restart_mode = 'from_scratch' ,
outdir = '/home/olh/tmp/' ,
wfcdir = '/home/olh/work/' ,
pseudo_dir = '/home/olh/pseudo/' ,
prefix = 'Pt(111)_20' ,
tstress = .true. ,
tprnfor = .true. ,
/
&SYSTEM
ibrav = 0,
A = 5.549 ,
B = 5.549 ,
C = 21.062 ,
cosAB = -0.5 ,
cosAC = 0 ,
cosBC = 0 ,
nat = 20,
ntyp = 1,
ecutwfc = 40 ,
ecutrho = 160 ,
occupations = 'smearing' ,
degauss = 0.02 ,
smearing = 'gaussian' ,
nr1 = 1 ,
nr2 = 1 ,
nr3 = 1 ,
/
&ELECTRONS
conv_thr = 1.0D-8 ,
mixing_beta = 0.7D0 ,
diagonalization = 'david' ,
/
CELL_PARAMETERS cubic
10.486467456 0.000000000 0.000000000
-5.243233728 9.081547213 0.000000000
0.000000000 0.000000000 39.801219799
ATOMIC_SPECIES
Pt 195.09000 Pt.pz-rrkjus.linux.UPF
ATOMIC_POSITIONS angstrom
Pt -0.000000000 0.000000000 -9.062000000 0 0 0
Pt -0.000000000 2.775000000 -9.062000000 0 0 0
Pt 2.403000000 -1.387000000 -9.062000000 0 0 0
Pt 2.403000000 1.387000000 -9.062000000 0 0 0
Pt -0.000000000 -0.000000000 -2.265000000 0 0 0
Pt -0.000000000 2.775000000 -2.265000000 0 0 0
Pt 2.403000000 -1.387000000 -2.265000000 0 0 0
Pt 2.403000000 1.387000000 -2.265000000 0 0 0
Pt 1.602000000 0.000000000 -4.531000000 0 0 0
Pt 1.602000000 2.775000000 -4.531000000 0 0 0
Pt 4.005000000 -1.387000000 -4.531000000 0 0 0
Pt 4.005000000 1.387000000 -4.531000000 0 0 0
Pt 0.801000000 1.387000000 -6.796000000 1 1 1
Pt 0.801000000 4.162000000 -6.796000000 1 1 1
Pt 3.204000000 0.000000000 -6.796000000 1 1 1
Pt 3.204000000 2.775000000 -6.796000000 1 1 1
Pt 0.801000000 1.387000000 -0.000000000 1 1 1
Pt 0.801000000 4.162000000 -0.000000000 1 1 1
Pt 3.204000000 -0.000000000 -0.000000000 1 1 1
Pt 3.204000000 2.775000000 -0.000000000 1 1 1
K_POINTS automatic
2 2 2 1 1 1
Lihui Ou
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