[Pw_forum] about the parameter beta

Eyvaz Isaev eyvaz_isaev at yahoo.com
Thu Mar 10 22:13:52 CET 2005


As usual \rho_{n+1}(in) = (1-\alpha)\rho_{n}(in) +
\alpha \rho_{n}(out).
So, it seems, yes, that is. But one have to be
careful, because the Broyden method is used by default
for charge mixing. In this case the  above mentioned
mixing procedure is used just for a few initial


--- Aritz Leonardo <swblelia at sw.ehu.es> wrote:
> One simple question: A big value of beta means a
> small portion of the previous density?
> this is...  n(i+1) = beta*n + (1-beta)*n(i)

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