<html>Dear all,<br /><br />While reading pp.x description:<br />the plot num= 1 plots 'V_bare+V_H+V_xc'<br />the plot num=11 plots 'V_bare+V_H'<br />the plot num=2 plots 'V_bare'<br />Then, it seems then that:<br />to obtain V_H, a substraction of plot 11-plot 2 is enough.<br />to obtain V_xc, a substraction of plot 1-plot 11 is enough.<br /><br />However, while V_bare is well described by a ~1/r, its screening with Hartree potential sould be ~1/r*exp(-r/lengh).<br />Then the exponential V_H sould be the division plot11/plot2?<br />Or is it an exact value ADDED to V_bare and calculated with the Poisson equation?<br /><br />Antoine Jay<br />LAAS-CNRS, Toulouse France<br /><br /><br /> </html>