<div dir="ltr"><div><div><div><div><div>dear Paolo,<br><br></div>Tsung-Lung Li explained the atoms will be moved idependently according to the forces acting on them.<br></div>And you said that is correct. It seems to me that somehow contradicts to say that this still preserves the symmetry.<br></div>Please clarify if I'm wrong about this. Because I understand right to keep the symmetry the atoms should be moved not only according to their forces, but also preserving their coordinates, which suggests that their should move isotropically, right?<br><br></div>Thank you very much,<br><br></div>Ricardo.<br></div><div class="gmail_extra"><br><div class="gmail_quote">On 5 October 2017 at 14:09, Paolo Giannozzi <span dir="ltr"><<a href="mailto:p.giannozzi@gmail.com" target="_blank">p.giannozzi@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir="ltr"><span class="">On Thu, Oct 5, 2017 at 4:03 PM, Tsung-Lung Li <span dir="ltr"><<a href="mailto:quantum@mail.ncyu.edu.tw" target="_blank">quantum@mail.ncyu.edu.tw</a>></span> wrote:<br><br></span><div class="gmail_extra"><div class="gmail_quote"><span class=""><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
It seems to me QE does the following.<br>
<br>
1. Initially, QE uses space_group and the 7 inequivalent atoms in<br>
ATOMIC_POSITIONS to produce 24 atoms in the crystal unit cell.<br></blockquote><div><br></div></span><div>correct<br> <br></div><span class=""><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
2. In each subsequent geometric step of the 'relax' calculation,<br>
the 24 atoms are moved independently according to the forces<br>
acting on each atom.<br></blockquote><div><br></div></span><div>correct<br> <br></div><span class=""><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
Therefore, at the end of the 'relax' calculation, the space_group=15 symmetry is not always preserved.<br></blockquote><div><br></div></span><div>not correct. Structural optimization based on forces does not break the symmetry, with occasional unfortunate exceptions due to numerical noise<br> <br></div><span class=""><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
Can QE only move the 7 inequivalent atoms and use space_group symmetry to construct the other 17 atoms for next geometric step?<br></blockquote><div><br></div></span><div>It could be done in principle, but it would require some extensive changes to the structural optimization algorithm, with dubious advantages in return.<br></div><div> <br></div><div>Paolo<br><br></div><div><div class="h5"><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
This way, the space_group symmetry will be preserved at the end of the simulation.<br>
<br>
Thank you in advance.<br>
<br>
Best Regards,<br>
Tsung-Lung Li<br>
<br>
------------------------------<wbr>------------------------------<wbr>------<br>
&control<br>
calculation = 'relax'<br>
restart_mode = 'from_scratch'<br>
/<br>
&system<br>
space_group = 15<br>
celldm(1) = 11.86181088389489 ! bohr<br>
celldm(2) = 2.41851202803887<br>
celldm(3) = 0.903616377250279<br>
celldm(5) = -0.408489773780522<br>
ntyp = 4<br>
nat = 7<br>
/<br>
<br>
ATOMIC_SPECIES<br>
Ca 40.0780000000 Ca_pbe_v1.uspp.F.UPF<br>
S 32.0650000000 S_pbe_v1.2.uspp.F.UPF<br>
O 15.9994000000 O.pbe-n-kjpaw_psl.0.1.UPF<br>
H 1.0079000000 H.pbe-rrkjus_psl.0.1.UPF<br>
<br>
ATOMIC_POSITIONS crystal_sg<br>
Ca 0.00000 0.17050 0.25000<br>
S 0.00000 0.32727 0.75000<br>
O 0.08319 0.27218 0.59103<br>
O 0.19997 0.38195 0.91298<br>
O -0.20823 0.06826 -0.07831<br>
H -0.25800 0.08700 -0.23400<br>
H -0.24400 0.02000 -0.07700<br>
<br>
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