No, it is a local but orbital dependent functional. In other words, the Hartree potential does not couple different orbitals and has a diagonal matrix while the Hartree-Fock potential has non-diagonal matrix elements which couple different orbitals.<br>
Bests<br>S.J. Hashemifar <br clear="all"><div>======================================<br>Seyed Javad Hashemifar<br>Department of Physics, Isfahan University of Technology<br>84156-83111 Isfahan, Iran<br>Tel: +98 311 391 2375 Fax:+98 311 3912376<br>
Email: <a href="mailto:hashemifar@cc.iut.ac.ir" target="_blank">hashemifar@cc.iut.ac.ir</a><br>Group Homepage: <a href="http://cmsgroup.iut.ac.ir" target="_blank">http://cmsgroup.iut.ac.ir</a><br>Personal Homepage: <a href="http://hashemifar.iut.ac.ir" target="_blank">http://hashemifar.iut.ac.ir</a><br>
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<br><br><div class="gmail_quote">On Sat, Jan 26, 2013 at 4:14 PM, Caloma Trumica <span dir="ltr"><<a href="mailto:spmmal@gmail.com" target="_blank">spmmal@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
Dear <span style="color:rgb(34,34,34);font-size:13px;font-family:arial,sans-serif">Hashemifar,</span><div><font color="#222222" face="arial, sans-serif"><br></font></div><div><font color="#222222" face="arial, sans-serif">Thanks for your reply.</font></div>
<div><font color="#222222" face="arial, sans-serif"><br></font></div><div><font color="#222222" face="arial, sans-serif">But the Hartree energy term in the Hamiltonian is also non-local. Isn't it?</font></div><div><font color="#222222" face="arial, sans-serif"><br>
</font></div><div><font color="#222222" face="arial, sans-serif">Andy<br></font><div><div class="h5"><br><div class="gmail_quote">On Sat, Jan 26, 2013 at 1:14 AM, Seyed Javad Hashemifar <span dir="ltr"><<a href="mailto:hashemifar@cc.iut.ac.ir" target="_blank">hashemifar@cc.iut.ac.ir</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">My understanding is that, in the HSE functional, 25% of the short range componet of PBE exchange interaction is replaced with Hartree-Fock exchange, hence in this kind of calculations, you have a non-local orbital dependent Hamiltonian. As a result of that the computations are significantly more expensive that the calculations by using local LDA or semi-local GGA functionals.<br>
<br>Regards<br>SJ Hashemifar<br clear="all"><div>======================================<br>Seyed Javad Hashemifar<br>Department of Physics, Isfahan University of Technology<br>84156-83111 Isfahan, Iran<br>Tel: <a href="tel:%2B98%20311%20391%202375" value="+983113912375" target="_blank">+98 311 391 2375</a> Fax:<a href="tel:%2B98%20311%203912376" value="+983113912376" target="_blank">+98 311 3912376</a><br>
Email: <a href="mailto:hashemifar@cc.iut.ac.ir" target="_blank">hashemifar@cc.iut.ac.ir</a><br>Group Homepage: <a href="http://cmsgroup.iut.ac.ir" target="_blank">http://cmsgroup.iut.ac.ir</a><br>Personal Homepage: <a href="http://hashemifar.iut.ac.ir" target="_blank">http://hashemifar.iut.ac.ir</a><br>
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<br><br><div class="gmail_quote"><div><div>On Sat, Jan 26, 2013 at 5:14 AM, Caloma Trumica <span dir="ltr"><<a href="mailto:spmmal@gmail.com" target="_blank">spmmal@gmail.com</a>></span> wrote:<br></div>
</div><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div><div>
Dear All,<div><br></div><div>I have a quick question:</div><div><br></div><div>why the HSE-type calculations are much more time consuming than standard DFT calculations.</div><div><br></div><div>Thanks.</div><div><br></div>
<div>Andy</div>
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