On 20 October 2012 12:59, karan deep <span dir="ltr"><<a href="mailto:karandeepster@gmail.com" target="_blank">karandeepster@gmail.com</a>></span> wrote:<br><div class="gmail_quote"><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div class="im"><div><span style="color:rgb(34,34,34);font-family:arial,sans-serif;font-size:13px">>in order to get exactly the same number, you have to use either</span></div></div><div><div class="im">
<span style="color:rgb(34,34,34);font-size:13px;font-family:arial,sans-serif">>a converged grid of k-points, or exactly the same k-points.</span></div></div><div><span style="color:rgb(34,34,34);font-family:arial,sans-serif;font-size:13px;background-color:rgb(255,255,255)">i try the example 2 of silicon which has 10 k-points mentioned in it for both sc and fcc.</span></div>
<div>any suggestions please</div><div><br></div><div></div></blockquote></div><div><br></div><div><br></div><div>"exactly the same k points" does not mean "copy and paste the list of points". You have to reduce the list for the unit cell to a certain subset according to the cell->supercell mapping of the Brillouin zone.</div>
<div><br></div><div>I.e. the Gamma point in the SC cell becomes Gamma (weight 1/4) + X =a/2pi(1 0 0) (weight 3/4) in the FCC cell. In general it is not easy, you will need to think some time (let's say a few hours) about it.</div>
<div><br></div><div>bests</div><div><div><br></div>-- <br><div>Dr. Lorenzo Paulatto </div><div>IdR @ IMPMC -- CNRS & Université Paris 6</div><div>phone: +33 (0)1 44275 084 / skype: paulatz</div><div>www: <a href="http://www-int.impmc.upmc.fr/~paulatto/" target="_blank">http://www-int.impmc.upmc.fr/~paulatto/</a></div>
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