<DIV>Dear pwscf users,<BR>   I have a question, quite naive. I tried to search the pdos of oxygen molecular, </DIV>
<DIV>but I have to rely on your advice. as well as I know,the calculation procedes as </DIV>
<DIV>follows:<BR>1) make a self-consistent calculation (input=O2.scf.in)<BR>2) run a non-self-consistent calculation (input=O2.nscf.in)<BR>3) run projwfc.x program (input=O2.pdos.in, output=O2.pdos.out)in order to produce a </DIV>
<DIV>postscript file: O2.pdos_tot.<BR>    After scf and nscf calculation, the program pdos was used as follows:<BR>&CONTROL<BR> 1)scf calculation:              <BR>                 calculation = 'scf' ,<BR>                restart_mode = 'from_scratch' ,<BR>                      outdir = '/home/olh/tmp/' ,<BR>                  pseudo_dir = '/home/olh/pseudo/' ,<BR>                      prefix = 'O2' ,<BR> /<BR> &SYSTEM<BR>                       ibrav = 4,<BR>                   celldm(1) = 10.486,<BR>                   celldm(3) = 2.979,<BR>                         nat = 2,<BR>                        ntyp = 1,<BR>                     ecutwfc = 30 ,<BR>                     ecutrho = 300 ,<BR>                 occupations = 'smearing' ,<BR>                     degauss = 0.02 ,<BR>                    smearing = 'methfessel-paxton' ,<BR>                       nspin = 2 ,<BR>   starting_magnetization(1) = 0.5,<BR> /<BR> &ELECTRONS<BR>                    conv_thr = 1.D-6 ,<BR>                 mixing_beta = 0.4D0 ,<BR>             diagonalization = 'david' ,<BR> /<BR>ATOMIC_SPECIES<BR>    O   15.99900  O.pbe-rrkjus.UPF <BR>ATOMIC_POSITIONS angstrom <BR>    O     -1.553621017    5.696221321    6.037977498    0  0  0 <BR>    O     -2.611378983    6.337778679    6.038022502    0  0  0 <BR>K_POINTS automatic <BR>  4 4 1   1 1 1 </DIV>
<DIV>2) nscf calculation:<BR> &CONTROL<BR>                 calculation = 'nscf' ,<BR>                restart_mode = 'from_scratch' ,<BR>                      outdir = '/home/olh/tmp/' ,<BR>                  pseudo_dir = '/home/olh/pseudo/' ,<BR>                      prefix = 'O2' ,<BR> /<BR> &SYSTEM<BR>                       ibrav = 4,<BR>                   celldm(1) = 10.486,<BR>                   celldm(3) = 2.979,<BR>                         nat = 2,<BR>                        ntyp = 1,<BR>                     ecutwfc = 30 ,<BR>                     ecutrho = 300 ,<BR>                 occupations = 'smearing' ,<BR>                     degauss = 0.02 ,<BR>                    smearing = 'methfessel-paxton' ,<BR>                       nspin = 2 ,<BR>   starting_magnetization(1) = 0.5,<BR> /<BR> &ELECTRONS<BR>                    conv_thr = 1.D-6 ,<BR>                 mixing_beta = 0.4D0 ,<BR>             diagonalization = 'david' ,<BR> /<BR>ATOMIC_SPECIES<BR>    O   15.99900  O.pbe-rrkjus.UPF <BR>ATOMIC_POSITIONS angstrom <BR>    O     -1.553621017    5.696221321    6.037977498    0  0  0 <BR>    O     -2.611378983    6.337778679    6.038022502    0  0  0 <BR>K_POINTS automatic <BR>  4 4 1   1 1 1</DIV>
<DIV>3) pdos calculation: <BR> &INPUTPP<BR>                      prefix = 'O2' ,<BR>                      outdir = '/home/olh/tmp/' ,<BR>                      ngauss = 1,<BR>                     degauss = 0.02,<BR>                      DeltaE = 0.01 ,<BR>                        Emin = -35 ,<BR>                        Emax = -4 ,<BR> /<BR>    However, when I calculated pdos, in order to produce a postscript file: </DIV>
<DIV>O2.pdos_tot, I encounter a problem, output is displayed as follows:<BR>......<BR>k =  -0.3750000000 -0.2165063509  0.1678415576<BR>     e =   -30.88771 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -18.42806 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -12.12292 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -10.97042 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -10.96565 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =    -4.27073 eV<BR>     psi = <BR>    |psi|^2 =   NaN</DIV>
<DIV> k =   0.0000000000 -0.4330127019 -0.1678415576<BR>     e =   -30.88770 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -18.42864 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -12.12059 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -10.96946 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =   -10.96552 eV<BR>     psi = <BR>    |psi|^2 =   NaN<BR>     e =    -4.27538 eV<BR>     psi = <BR>    |psi|^2 =   NaN</DIV>
<DIV>Lowdin Charges: </DIV>
<DIV>     Atom #   1: total charge =      NaN, s, p, d, f =      NaN     NaN<BR>                 spin up      =      NaN, s, p, d, f =      NaN     NaN<BR>                 spin down    =      NaN, s, p, d, f =      NaN     NaN<BR>                 polarization =      NaN, s, p, d, f =      NaN     NaN<BR>     Atom #   2: total charge =      NaN, s, p, d, f =      NaN     NaN<BR>                 spin up      =      NaN, s, p, d, f =      NaN     NaN<BR>                 spin down    =      NaN, s, p, d, f =      NaN     NaN<BR>                 polarization =      NaN, s, p, d, f =      NaN     NaN<BR>     Spilling Parameter:      NaN<BR>It displayed "NaN", not numerical, I am confused.<BR>Any suggestions is appreciated.</DIV>
<DIV> </DIV>
<DIV>Thank you in advance<BR>Lihui Ou<BR></DIV>
<DIV> </DIV>
<DIV> </DIV>
<DIV><BR>--<BR>
<DIV>
<DIV><FONT face="Arial" size="3">======================================</FONT></DIV>
<DIV><FONT face="Arial" size="3">Lihui Ou</FONT></DIV>
<DIV><FONT face="Arial" size="3">PH.D Candidate in Electrochemistry                      </FONT></DIV>
<DIV><FONT face="Arial" size="3">College of Chemistry and Molecular Science            </FONT></DIV>
<DIV><FONT face="Arial" size="3">Wuhan University,<EM>430072</EM>,Hubei Province,China </FONT></DIV>
<DIV><EM><FONT face="Arial" size="3">E-mail:</FONT><A href="mailto:oulihui666@126.com" target="_blank"><FONT face="Arial" size="3">oulihui666@126.com</FONT></A></EM></DIV>
<DIV><FONT face="Arial" size="3">======================================</FONT></DIV></DIV></DIV>