[Pw_forum] How to get absorption coefficient

[Timrov Iurii]

Dear Clarence,


Before continuing using turboTDDFT, I strongly recommend to read (at least) these two publications:


1. turboTDDFT - A code for the simulation of molecular spectra using the Liouville-Lanczos approach
to time-dependent density-functional perturbation theory  Original Research Article
Authors: Osman Baris Malcioglu, Ralph Gebauer, Dario Rocca, Stefano Baroni
Source: Computer Physics Communications   Volume: 182  Article Number: 1744  Published: APR 2011

2. turboTDDFT 2.0 - Hybrid functionals and new algorithms within time-dependent
density-functional perturbation theory
Authors: X. Ge, S. J. Binnie, D. Rocca, R. Gebauer, and S. Baroni
Source: Computer Physics Communications  Volume: 185  Article Number: 2080  Published: MAR 2014


The full list of publications about the TDDFPT module of Quantum ESPRESSO can be found in qe/TDDFPT/README.


The 3x3 matrix chi_i_j is the polarizability (i and j run over the Cartesian components x, y, z, which in the plot_chi.dat file correspond to 1, 2, 3, respectively) - see Eq.(5) in the first reference mentioned above. In the file *.plot_chi.dat in the header you can see what is the meaning of each column, i.e.:

second column - energy \hbar \omega (Ry)

third column      - real part of the polarizability Re(chi)

fourth column    - imaginary part of the polarizability Im(chi)


In the same plot_chi.dat file, there is also the information (only if you performed Lanczos calculations along three Cartesian directions, i.e. ipol=4 - see the first reference above) about S(E) (second column) as a function of the energy (first column), which is the oscillator strength (the absorption coefficient). It is defined as (see the output file produced by turbo_spectrum.x, i.e. *.tddfpt_pp-out):


S(\hbar \omega) = 2m/( 3 \pi e^2 \hbar)  \omega sum_j chi_j_j


HTH


Regards,

Iurii


--
Dr. Iurii Timrov
Postdoctoral Researcher
Swiss Federal Institute of Technology Lausanne (EPFL)
Laboratory of Theory and Simulation of Materials (THEOS)
CH-1015 Lausanne, Switzerland
+41 21 69 34 881
http://people.epfl.ch/265334
________________________________
From: pw_forum-bounces at pwscf.org <pw_forum-bounces at pwscf.org> on behalf of LEUNG Clarence <liangxy123 at hotmail.com>
Sent: Monday, July 31, 2017 4:27 PM
To: pw_forum at pwscf.org
Subject: [Pw_forum] How to get absorption coefficient


Dear QE users,


Now, I use the turbo_lanczos.x and turbo_spectrum to get the absorption spectrum.


I can get a plot_chi.dat file, as follow:


#Chi is reported as CHI_(i)_(j) \hbar \omega (Ry)  Re(chi) (e^2*a_0^2/Ry) Im(chi) (e^2*a_0^2/Ry)
# S(E) satisfies the sum rule
     chi_1_1=  0.000000000000000E+00  0.189914943334197E+04  0.000000000000000E+00
     chi_2_1=  0.000000000000000E+00  -.949575309581559E+03  0.000000000000000E+00
     chi_3_1=  0.000000000000000E+00  -.843216803071169E-03  0.000000000000000E+00
     chi_1_2=  0.000000000000000E+00  -.949574977107089E+03  0.000000000000000E+00
     chi_2_2=  0.000000000000000E+00  0.189915026381885E+04  0.000000000000000E+00
     chi_3_2=  0.000000000000000E+00  0.110034487599961E-03  0.000000000000000E+00
     chi_1_3=  0.000000000000000E+00  -.838178086194996E-03  0.000000000000000E+00
     chi_2_3=  0.000000000000000E+00  0.109036445082823E-03  0.000000000000000E+00
     chi_3_3=  0.000000000000000E+00  0.153710402502629E+03  0.000000000000000E+00


What is meaning of each row and how can I get the absorption coefficients?


Many thanks.


Clarence

City University of Hong Kong
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